Open access peer-reviewed chapter

A Study on Numerical Solution of Fractional Order microRNA in Lung Cancer

Written By

Mohammed Baba Abdullahi and Amiru Sule

Submitted: 21 December 2022 Reviewed: 20 March 2023 Published: 17 May 2023

DOI: 10.5772/intechopen.111387

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PID Control for Linear and Nonlinear Industrial Processes

Edited by Mohammad Shamsuzzoha and G. Lloyds Raja

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Abstract

The foremost cause of death resulting from cancer is lung cancer. From the statistics, 2.09 million new cases and 1.7 million deaths from lung cancer were estimated. In this chapter, the analytical solution of the concerned model was studied with help of the Laplace-Adomian Decomposition Method. To obtain the model’s numerical scheme of fractional differential equations, the Caputo fractional derivative operator of order α∈01 is used. To find an approximate solution to a system of nonlinear fractional differential equations, the Laplace-Adomian Decomposition Method is used. Numerical simulations are presented to show the method’s reliability and simplicity.

Keywords

  • fractional order
  • microRNA
  • numerical solution
  • cancer-related deaths
  • lung cancer

1. Introduction

The largest cause of cancer-related deaths worldwide is lung cancer. In the United States, a projected 236,740 people will receive a lung cancer diagnosis in 2022, making it the 16th most common cancer overall (1 in 15 males and 1 in 17 women). Smoking causes 80% of lung cancer fatalities and is the main risk factor for the disease. Twenty percent of lung cancer deaths occur in people who have never smoked. The second most important risk factor for lung cancer is radon gas exposure [1, 2]. Depending on the average radon level and the incidence of smoking in a nation, radon contributes to anywhere between 3 and 14% of lung cancer cases. Smokers are 25 times more likely than non-smokers to develop lung cancer from radon than non-smokers are likely to develop the cancer [3].

Early detection of high-risk lung cancer cases can reduce the chance of death by up to 20%. If you smoke now or have in the past, ask your doctor if lung cancer screening may be right for you. Approximately 8 million Americans are at high risk for lung cancer and could benefit from a lung cancer screening and yet only 5.7% actually get screened [4]. The dismal statistics associated with lung cancer are a result of both a lack of early detection and a lack of effective target therapy. Therefore, it is likely that developments in both of these areas will end in better results.

MicroRNAs (miRNAs) are a class of short nonprotein-coding RNAs (20–25 nucleotides in length) that predominantly inhibit the expression of target messenger RNAs (mRNAs) by directly interacting with their 30-untranslated regions (30UTRs) [5]. Numerous biological processes, from organismic development to tumor progression, depend on microRNAs in one way or another. These microRNAs have a crucial regulatory function in the pathogenesis of cancer in oncology, which forms the basis for investigating the influences on clinical characteristics using transcriptome data [6]. The seed match architecture between the mRNA seeding and miRNA binding regions determines the fate of the target mRNA. Perfect miRNA complementarity with the seeding sequence induces mRNA degradation, but imperfect or partial complementarities decrease protein translation [5].

Given the fact that a single miRNA may regulate tens to hundreds of genes, understanding the importance of an individual miRNA in cancer biology can be challenging. This is further complicated by observations that the dysregulation of several miRNAs is often required to cause a given phenotype [7]. To date, few models exist to elucidate the mechanisms by which multiple miRNAs contribute both individually and in tandem to promote tumor initiation and progression [8]. However, applying mathematical modeling to miRNA biology provides an opportunity to understand these complex relationships. In the work of Bersimbaev et al. [8], they developed for the first time a mathematical model focusing on miRNAs (miR-9 and let-7) in the context of lung cancer as a mathematical model system.

The organization of this chapter is as follows. In Section 2, some mathematical preliminaries of fractional calculus are needed to demonstrate the main results. The formulation of the Laplace-Adomian Decomposition Method (LADM) and Differential Transform Method (DTM) are given in Section 3. In Section 4, the numerical simulations are presented. In Section 5, the conclusions are given.

For the details of the integer mathematical model see Ref. [8], and the model is given below.

ddtSt=μSEStotSStotS+KS1δESkSS+KS2ddtRt=μRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3ddtEkt=μEkREktotEkEktotEk+KEk1δEkEkEk+KEk2ddtCt=μCEkδcCddtMt=μMC4C4+KMδMMddtLt=μLKLC+KLδLLddtHt=μHLKHM+KHδHHddtPt=μPδPPHH+KPE1

With the given initial condition.

S0=n1,R0=n2,Ek0=n3,C0=n4,M0=n5,L0=n6,H0=n7,P0=n8, where tables give the descriptions of the state variables and parameters.

cDα1St=μSEStotSStotS+KS1δESkSS+KS2cDα2Rt=μRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3cDα3Ekt=μEkREktotEkEktotEk+KEk1δEkEkEk+KEk2cDα4Ct=μCEkδcCDcα5Mt=μMC4C4+KMδMMcDα6Lt=μLKLC+KLδLLcDα7Ht=μHLKHM+KHδHHcDα8Pt=μPδPPHH+KPE2

With given initial condition.

S0=n1,R0=n2,Ek0=n3,C0=n4,M0=n5,L0=n6,H0=n7,P0=n8, where.

cDα0<xi1fori=0,1,2 is the Caputo’s derivate of fractional order and x shows fractional time derivative.

In model 2, the initial conditions are independent of each other and satisfy the relation.

N0=St+Rt+Ekt+Ct+Mt+Lt+Ht+Pt, whereNtis the total population.

S0=n1,R0=n2,Ek0=n3,C0=n4,M0=n5,L0=n6,H0=n7,P0=n8E3
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2. Preliminaries

This section focuses on some basic definitions and outcomes from fractional calculus. For more in-depth, detailed research [9, 10, 11].

Definition 2.1. The fractional integral of Riemann-Liouville type of order α01 of a function fL10T is defined as:

The Caputo fractional order derivative of a function f on the interval at 0T is defined by the following:

cD0+αft=1Γα01tsnα1fnsds,E4

when n=x+1andx represents the integer part of x. In particularity, for 0<x<1, Caputo derivative becomes

cD0+αft=1Γα01fs1sds.E5

Lemma 2.1. The next outcome holds for fractional differential equations.

IαcDαht=ht+i=0n1hi0i!ti.E6
for  arbitraryx>0,i=0,1,2,,n1,whenn=x+1andxrepresentsthe integer part ofx

Definition 2.2. We recall the definition of Laplace transform of Caputo derivative as:

cDαyt=sαhsk=0n1sαi1yk0,n1<α<n,nN.E7
for  arbitraryx>0,i=0,1,2,,n1,whenn=x+1andxrepresentsthe integer part ofx.

2.1 The Laplace-Adomian decomposition method

This section focuses on model (3)‘s overall operation under specified initial conditions. When both sides of the model are transformed using the Caputo fractional derivative system (3), the following results are obtained:

LcDα1St=μSEStotSStotS+KS1δESkSS+KS2LcDα2Rt=μRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3LcDα3Ekt=μEkREktotEkEktotEk+KEk1δEkEkEk+KEk2LcDα4Ct=μCEkδcCLDcα5Mt=μMC4C4+KMδMMLcDα6Lt=μLKLC+KLδLLLcDα7Ht=μHLKHM+KHδHHLcDα8Pt=μPδPPHH+KPE8

thus indicates

sα1LcDα1Stsα11S0=LμSEStotSStotS+KS1δESkSS+KS2sα2LcDα2Rtsα11R0=LμRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3sα3LcDα3Ektsα11Ek0=LμEkREktotEkEktotEk+KEk1δEkEkEk+KEk2sα4LcDα4Ctsα11C0=LμCEkδcCsα5LDcα5Mtsα11M0=LμMC4C4+KMδMMsα6LcDα6Ltsα11L0=LμLKLC+KLδLLsα7LcDα7Htsα11H0=LμHLKHM+KHδHHsα8LcDα8Ptsα11P0=LμPδPPHH+KPE9

Using the initial conditions and taking inverse Laplace transform to system (5), we have:

St=S0+L1μSEStotSStotS+KS1δESkSS+KS2Rt=R0+L1μRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3Ekt=Ek0+L1μEkREktotEkEktotEk+KEk1δEkEkEk+KEk2Ct=C0+L1μCEkδcCMt=M0+L1μMC4C4+KMδMMLt=L0+L1μLKLC+KLδLLHt=H0+L1μHLKHM+KHδHHPt=P0+L1μPδPPHH+KPE10

Using the values of the initial condition in Eq. (6), we get:

St=n1+L1μSEStotSStotS+KS1δESkSS+KS2Rt=n2+L1μRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3Ekt=n3+L1μEkREktotEkEktotEk+KEk1δEkEkEk+KEk2Ct=n4+L1μCEkδcCMt=n5+L1μMC4C4+KMδMMLt=n6+L1μLKLC+KLδLLHt=n7+L1μHLKHM+KHδHHPt=n8+L1μPδPPHH+KPE11

Assume that the solutions, St,Rt,Ekt,Ct,Mt,Lt,Ht,Pt in the form of infinite series, are given by:

St=n=0Stn,Rt=n=0Rtn,Ekt=n=0Ektn.Ct=n=0CtnMt=n=0Mtn,Lt=n=0Ltn,Ht=n=0Htn.Pt=n=0PtnE12

While the nonlinear term involved in the model is StEkt,StRt,FtRt,PtHt and is decomposed as follows, where Xn,YnandZn are the Adomian polynomials defined as are:

Xn=1Γn+1dndtnk=0λkSkk=0λkEkkλ=0Yn=1Γn+1dndtnk=0λkSkk=0λkRkλ=0Zn=1Γn+1dndtnk=0λkEkkk=0λkRkλ=0Wn=1Γn+1dndtnk=0λkPkk=0λkHkλ=0E13

The first three polynomials are given by:

X0=S0tEk0t,X1=S0tEk1t+S1tEk0tX2=2S0tEk2t+2S1tEk1t+2S2tEk0tY0=S0tR0t,Y1=S0tR1t+S1tR0tY2=2S0tR2t+2S1tR1t+2S2tR0tZ0=Ek0tR0t,Z1=Ek0tR1t+Ek1tR0tZ2=2Ek0tR2t+2Ek1tR1t+2Ek2tR0tW0=P0tH0t,W1=P0tH1t+P1tH0tW2=2P0tH2t+2P1tH1t+2P2tH0E14

Using Eqs. (8) and (10) in model (6), yields

Ln=0Skt=S0s+1sαLμSEStotSStotS+KS1δESkSS+KS2Ln=0Rkt=R0s+1sαLμRSRtotRRtotR+KR1KR2L+KR2δRRR+KR3Ln=0Ekkt=Ek0s+1sαLμEkREktotEkEktotEk+KEk1δEkEkEk+KEk2Ln=0Ckt=C0s+1sαLμCEkδcCLn=0Mkt=M0s+1sαLμMC4C4+KMδMMLn=0Lkt=L0s+1sαLμLKLC+KLδLLLn=0Hkt=H0s+1sαLμHLKHM+KHδHHLn=0Pkt=P0s+1sαLμPδPPHH+KPE15

Now, comparing like terms on both sides, yields

LS0t=n1s,LR0t=n2s,LEk0t=n3s,LC0t=n4s,LM0t=n5s,LL0t=n6s,LH0t=n7s,LP0t=n8s,LS1=μSEsαStotS0StotS0+KS1δSsαX0S0+KS21sα1+1,LR1=μRS0RtotRtotR0+KR1KR2L0+KR2μRY0RtotR0+KR1KR2L0+KR2δRR0R0+KR31sα2+1,LEk1=μEkR0EktotEktotEk0+KEk1μEkZ0EktotEk0+KEk1δEkEk0Ek0+KEk21sα3+1,LC1=μCEk0δcC01sα4+1,LM1=μMC04C04+KMδMM01sα5+1,LL1=μLKLC0+KLδLL01sα6+1,LH1=μHL0KHM+0KHδHH01sα7+1,LP1=μPδPW0H0+KP1sα8+1,LSn+1=μSEStotSnStotSn+KS1δSXnSn+KS21sα1+1,LRn+1=μRSnRtotRtotRn+KR1KR2Ln+KR2μRYnRtotRn+KR1KR2Ln+KR2δRRnRn+KR31sα2+1,LEkn+1=μEkRnEktotEktotEkn+KEk1μEkZnEktotEkn+KEk1δEkEknEkn+KEk21sα3+1,LCn+1=μCEknδCCn1sα4+1,LMn+1=μMCn4Cn4+KMδMMn1sα5+1,LLn+1=μLKLCn+KLδLLn1sα6+1,LHn+1=μHLnKHM+nKHδHHn1sα7+1,LPn+1=μPδPWnHn+KP1sα8+1.E16

Taking Laplace inverse of (11) and considering the first two terms at different values ofα=1,0.95,0.85and0.75: and using the following values in Tables 1 and 2.

VariablesDescriptionValuesReferences
StActive SOS concentration0.0298 μm[7]
RtActive Ras concentration0.0053 μm[7]
EktActive ERK concentration0.2488 μm[7]
CtMYC protein concentration0.2189 μm[7]
MtmiR-9 concentration1.8x10−5 μm[7]
Ltlet-7 concentration0.0023 μm[7]
HtE-Cadherin concentration0.1 μm[7]
PtMMP mRNA concentration1.157x10−13 μm[7]

Table 1.

The state variables of the model.

VariablesDescriptionValuesReferences
E0Concentration of EGF-EGFR complex (Constant)0.2488 μM. μm[7]
StotTotal concentration of SOS0.2120 μm[7]
RtotTotal concentration of Ras0.2120 μm[7]
EktotTotal concentration of ERK1.0599 μm[7]
KS1Saturation of inactive SOS on active SOS10.7515 μm[7]
KS2Saturation of active SOS on inactive SOS0.0023 μm[7]
HtSaturation of inactive Ras on active Ras0.0635 μm[7]
KR2Control of let-7 on Ras0.0230 μm[7]
KR3Saturation of active Ras on inactive Ras2.5305 μm[7]
KEK1Saturation of inactive ERK on active ERK1.7795 μm[7]
KEK2Saturation of active ERK on inactive ERK6.1768 μm[7]
KMSaturation of MYC on miR-922.9606 μm[7]
KLControl of MYC on let-70.2189 μm[7]
KHControl of MYC on E-Cadherin1.8 × 10−5 μm[7]
KPControl of E-Cadherin on MMP mRNA0.1 μm[7]
μSCatalytic production rate of active SOS394.5868/μmmin[7]
μR0Catalytic production rate of active Ras32.344/min[7]
μEkCatalytic production rate of active ERK49.2683/min[7]
μCCatalytic production rate of MYC0.0184/min[7]
μMCatalytic production rate of miR-90.0026/μmmin[7]
μLCatalytic production rate of let-71.3340 × 10−5μm/min[7]
μHCatalytic production rate of E-Cadherin0.2087/min[7]
μPCatalytic production rate of MMP9.8379 × 10−17μm/min[7]
δS0Degradation rate of active SOS322.3940/min[7]
δRDegradation rate of active Ras319.9672 μm/min[7]
δEkDegradation rate of active ERK1.8848 μm/min[7]
δCDegradation rate of MYC protein0.0231/min[7]
δMDegradation rate of miR-90.0144/min[7]
δLDegradation rate of let-70.0029/min[7]
δHDegradation rate of E-Cadherin0.0024/min[7]
δPDegradation rate of MMP mRNA0.0017/min[7]

Table 2.

The parameters of the model.

From α=1,12obtained

St=394.5868+21.03377825t+39.51795700t2Rt=0.0053+8874.951815t+6221.509715t2Ekt=0.24880.00877591439t+62646.35055t2Ct=0.21890.00047867t+0.0000862605090t2Mt=0.000018+0.00002672931626t1.924510749x107t2Lt=0.0023+0.000006684617295t2Ht=0.10.00023333t+0.0000029641441673t2Pt=1.157x1013+3.4x1020t+4.941947609x1017t2E17

From α=0.95,12obtained

St=394.5868+21.46565321t0.95+41.36344349t1.90Rt=0.0053+9057.176303t0.95+6512.053888t1.90Ekt=0.24880.0047867t0.95+65571.93179t1.90Ct=0.21890.0004884982670t0.95+0.00009029571759t1.90Mt=0.000018+0.00002727813456t0.952.014385299x107t1.90Lt=0.0023+0.000006996788568t1.90Ht=0.10.000238120836t0.95+0.000003102566932t1.90Pt=1.157x1013+3.469810324x1020t0.95+5.17227363x1017t1.90E18

From α=0.85,1013obtained

St=394.5868+22.2435804t0.85+45.17936838t1.70Rt=0.0053+935.413409t0.85+7112.814038t1.70Ekt=0.24880.009280679638t0.85+71621.71589t1.70Ct=0.21890.0005062017158t0.85+0.0000986258194t1.70Mt=0.000018+0.00002826670933t0.852.200219512x107t1.70Lt=0.0023+0.000007642267217t1.70Ht=0.10.0002467504677t0.85+0.000003388789774t1.70Pt=1.157x1013+3.595581801020t0.85+5.649939635x1017t1.70E19

From α=0.75,12obtained

St=394.5868+22.88612324t0.75+49.1470382t1.50Rt=0.0053+9656.526685t0.75+7736.466899t1.50Ekt=0.24880.009548767504t0.75+77900.93395t1.50Ct=0.21890.0005208241943t0.75+0.000107273391t1.50Mt=0.000018+0.00002908324024t0.752.393135170x107t1.50Lt=0.0023+0.000008312342631t1.50Ht=0.10.0002538782653t0.75+0.000003685919493t1.50Pt=1.157x1013+3.699421857x1020t0.75+6.145327396x1017t1.50E20

2.2 Differential transform method

The following recurrence relation to the system (2) with respect to time t is obtained.

Sk+1=1k+1μSEStotSkStotSk+KS1kδSi=0nSlEkklSk+KS2,Rk+1=1k+1μRSkRtotRtotRk+KR1KR2Lk+KR2μRi=0nSlRklRtotRk+KR1KR2Lk+KR2δRRkRk+KR3,Ekk+1=1k+1μEkRkEktotEktotEkk+KEk1μEki=0nEklRklEktotEkk+KEk1δEkEkkEkk+KEk2,Ck+1=1k+1μCEkkδcCk,Mk+1=1k+1μMC4kC4k+KMδMMk,Lk+1=1k+1μLKLC0+KLδLLk,Hk+1=1k+1μHLkKHMk+KHδHHk,Pk+1=1k+1μPδPi=0nPlHklHk+KP,E21

The inverse differential transform of Skis defined as: When t0is taken as zero, the given function yx is declared by a finite series and the above equation can be written in the form St=i=02Skik.

By solving the above equation for

Sk+1,Rk+1,Ekk+1Ck+1,Mk+1,Lk+1,Hk+1andPk+1E22

up to order 2, we get the function.

Sk,Rk,EkkCk,Mk,Lk,HkandPkSk,Ek,IkandRk of respectively

St=i=02Skik,Rt=i=02Rkik,Ekt=n=0Ekkik,Ct=n=0CkikMt=n=0Mkik,Lt=n=0Lkik,Ht=n=0Hkik,Pt=n=0PkikE23
St=394.5868+21.03377825t+40.55133050t2Rt=0.0053+8874.951815t+6221.509905t2Ekt=0.24880.00877591439t+62646.35060t2Ct=0.21890.00047867t+0.0000862605090t2Mt=0.000018+0.00002672931626t1.924510768x107t2Lt=0.0023+0.000006684617295t2Ht=0.10.00023333t+0.0000029641441658t2Pt=1.157x1013+3.4x1020t+4.941947609x1017t2E24
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3. Numerical results

The plots below show the population of each compartment for different values of αii=1234 (Figures 18).

Figure 1.

The plot shows the population of active SOS concentration for αi,i=123.

Figure 2.

The plot shows the population of active Ras concentration for αi,i=123.

Figure 3.

The plot shows the population of active ERK concentration for αi,i=123.

Figure 4.

The plot shows the population of active MYC protein concentration for αi,i=123.

Figure 5.

The plot shows the population of miR-9 concentration for αi,i=123.

Figure 6.

The plot shows the population of let7 concentration for αi,i=123.

Figure 7.

The plot shows the population of E-cadherin concentration for αi,i=123.

Figure 8.

The plot shows the population of MMP in RNA concentration for αi,i=123.

3.1 The comparison plots of the LADM and DTM of different compartments

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4. Conclusion

In this chapter, a fractional order differential equation model is considered. The model was investigated and a scheme for the numerical solution for the fractional order differential equation microRNA in lung cancer using LADM (Figures 916). The LADM is an effective technique to solve nonlinear mathematical models and is extensively applied in engineering and applied mathematics. Applying Laplace-Adomian Decomposition Method to obtain the series solution of fractional the model and comparing the results of the model at α01 with the classical Differential Transform Method is the main contribution of the work. The solution obtained through this method strongly agrees with DTM as shown in Figures 116. The effect of fractional parameters on our obtained solutions is presented through graphs.

Figure 9.

The comparison plots of the dynamics of active SOS concentration using LADM and DTM.

Figure 10.

The comparison plots of the dynamics of active Ras concentration using LADM and DTM.

Figure 11.

The comparison plots of the dynamics of active ERK concentration using LADM and DTM.

Figure 12.

The comparison plots of the dynamics of MYC protein concentration using LADM and DTM.

Figure 13.

The comparison plots of the dynamics of miR-9 concentration using LADM and DTM.

Figure 14.

The comparison plots of the dynamics of let7 concentration using LADM and DTM.

Figure 15.

The comparison plots of the dynamics of E-cadherin concentration using LADM and DTM.

Figure 16.

The comparison plots of the dynamics of MMP mRNA concentration using LADM and DTM.

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Written By

Mohammed Baba Abdullahi and Amiru Sule

Submitted: 21 December 2022 Reviewed: 20 March 2023 Published: 17 May 2023