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Polynomials Related to Generalized Fibonacci Sequence

Written By

Manjeet Singh Teeth and Sanjay Harne

Submitted: 20 November 2022 Reviewed: 10 February 2023 Published: 21 April 2023

DOI: 10.5772/intechopen.110481

From the Edited Volume

Coding Theory Essentials

Edited by Dinesh G. Harkut and Kashmira N. Kasat

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Abstract

The Fibonacci polynomials are a polynomial sequence that can be considered as a generalization of the Fibonacci numbers. Fibonacci polynomials are defined by a recurrence relation: Fnx=xFn−1x+Fn−2x,n≥2 where F0=0,F1=1. The first few Fibonacci polynomials are F0=0, F0x=0, F1x=1, F2x=x, F3x=x2+1. In this chapter, we extend the Fibonacci recurrence relation to define the sequence {Kn} and will derive some properties of this sequence. We also define four comparison sequences {Pn}, {Qn}, {Rn}, and {Sn} and obtain some identities with the help of generating matrix.

Keywords

  • Fibonacci numbers
  • Fibonacci sequence
  • generating matrix
  • rabbit problem
  • Polynomials

1. Introduction

The Fibonacci sequence [1] receives its name from Leonardo Pisano, known as Fibonacci who was the most talented Italian mathematician of middle age. It is supposed that he was the first mathematician who introduced the Hindu-Arabic system of numbers to Italians. His work ‘Liber-Abaci’ (1202) is famous for this.

In the Liber Abaci, Leonardo states the famous “Rabbit Problem” for attaining the output of this rabbit problem.

1.1 Utilization of Fibonacci sequence in the study of famous rabbit problem

“How many pairs of rabbits are born of one pair in a year?” This problem is stated in the form: “Suppose a newly-born pair of rabbits, one male and one female, are put in a field. Rabbits are able to mate at the age of 1 month so that at the end of its second month a female can produce another pair of rabbits.”

Suppose that our rabbits never die and that the female always produces one new pair (one male and one female) every month from the second month on.

Leonardo also gave the solution to this problem and obtained the sequence of numbers as a result:

1,1,2,3,5,8,

This sequence is called the Fibonacci sequence. The Fibonacci sequence is defined by the recurrence relation as,

Fn=Fn1+Fn2,n>1

Waddilli, M.E. [2] has extended the Fibonacci recurrence relation to define the sequence {Kn}, where,

Kn=Kn1+Kn2+Kn3,n>3E1

where, K0,K1,K2 are given arbitrary algebraic integers.

Jaiswal, D.V. [3] has extended Fibonacci recurrence relation to define the sequence {Q0}, where,

Qn=Qn1+Qn2+Qn3+Qn4,n>4E2

where, Q0,Q1,Q2 are given arbitrary algebraic integers.

Harne, S. [4] has extended Fibonacci recurrence relation to define the sequence {Dn}, where,

Dn=Dn1+Dn2+Dn3+Dn4+Qn5,n>5E3

where, D0,D1,D2 are given arbitrary algebraic integers.

In this chapter, Teeth MS. [5] shall further extend the Fibonacci recurrence relation [6, 7, 8, 9, 10] to define the sequence {Cn} and shall discuss some properties of this sequence. We shall also consider the four comparison sequences {Pn}, {Qn}, {Rn}, and {Kn}.

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2. The generalized sequence as per our propose model {Kn}

We consider the following sequence,

Cn=C0,C1,C2,C3,.,Cn

where, C0,C1,C2,C3,C4,C5,C0 are arbitrary algebraic integers all of which are not zero and

Cn=Cn1+Cn2+Cn3+Cn4+Cn5+Cn6,n6E4

We also consider the sequence Pn=P0,P1,P2,P3,.,Pn.

where,

P0=C3C2C1C0P1=C4C3C2C1P2=C5C4C3C2P3=C6C5C4C3P4=C7C6C5C4E5
with,Pn=Cn1+Cn2+Cn3+Cn4+Cn5,n5E6

and Qn=Q0,Q1,Q2,Q3,.,Qn

where,

Q0=C4C3C2C1Q1=C5C4C3C2C1Q2=C6C5C4C3C2E7
with,Qn=Cn1+Cn2+Cn3+Cn4E8

and Rn=R0,R1,R2,R3,.,Rnwhere,

R0=C5C4C3C2C1C0R1=C6C5C4C3C2C1R2=C7C6C5C4C3C2R3=C8C7C6C5C4C3R4=C9C8C7C6C5C4E9
with,Rn=Cn1+Cn2+Cn3E10

and Sn=S0,S1,S2,S3,.,Snwhere,

S0=C6C5C4C3C2C1C0S1=C7C6C5C4C3C2C1S2=C8C7C6C5C4C3C2S3=C9C8C7C6C5C4C3S4=C10C9C8C7C6C5C4E11
with,Sn=Cn1+Cn2,n2E12

From (4) and (6) we have for n11

Pn=Cn2+Cn3+Cn4+Cn5+Cn6+Cn7+Cn3+Cn4Cn5+Cn6+Cn7+Cn8+Cn4+Cn5+Cn6+Cn7+Cn8+Cn9+Cn5+Cn6+Cn7+Cn8+Cn9+Cn10+Cn6+Cn7+Cn8+Cn9+Cn10+Cn11
Pn=Pn1+Pn2+Pn3+Pn4+Pn5+Pn6

Now, from Eqs. (5) and (6),

P10=C8+C7+C6+C5+C4+C7+C6+C5+C4+C3+C6+C5+C4+C3+C2+C5+C4+C3+C2+C1+C4+C3+C2+C1+C0+C7C6C5C4
P10=P9+P8+P7+P6+P5+P4
Similarly,P9=P8+P7+P6+P5+P4+P3
P8=P7+P6+P5+P4+P3+P2
P7=P6+P5+P4+P3+P2+P1

Hence, we have for n6

Pn=Pn1+Pn2+Pn3+Pn4+Pn5+Pn6E13

Proceeding on similar lines, it can be shown that for n6.

Qn=Cn2+Cn3+Cn4+Cn5+Cn6+Cn7+Cn3+Cn4+Cn5+Cn6+Cn7+Cn8+Cn4+Cn5+Cn6+Cn7+Cn8+Cn9+Cn5+Cn6+Cn7+Cn8+Cn9+Cn10Qn=Qn1+Qn2+Qn3+Qn4+Qn5+Qn6,n6E14

Proceeding on similar lines it can be shown that for n6

Rn=Cn2+Cn3+Cn4+Cn5+Cn6+Cn7+Cn3+Cn4+Cn5+Cn6+Cn7+Cn8+Cn4+Cn5+Cn6+Cn7+Cn8+Cn9Rn=Rn1+Rn2+Rn3+Rn4+Rn5+Rn6,n6E15

Proceeding on similar lines it can be shown that for n6

Sn=Cn2+Cn3+Cn4+Cn5+Cn6+Cn7+Cn3+Cn4+Cn5+Cn6+Cn7+Cn8,n6Sn=Sn1+Sn2+Sn3+Sn4+Sn5+Sn6,n6E16

Thus, the four sequences {Pn}, {Qn}, {Rn}, and {Sn} are special cases of sequence {Cn} and all obtained by taking different initial values [11, 12].

On taking,

C0=C1=C2=0,C3=C4=1,C5=2C0=C1=0,C2=1,C3=0,C4=1,C5=2C0=0,C1=1,C2=C3=0,C4=1,C5=2C0=1,C1=C2=C3=0,C4=1,C5=2C0=C1=C2=C3=0,C4=1,C5=2E17
0,0,0,1,1,2,4,8,16,32,63,Jn,
0,0,1,0,1,2,4,8,16,31,62,Kn,
0,1,0,0,1,2,4,8,15,30,59,Ln,
1,0,0,0,1,2,4,7,14,28,56,Mn,
0,0,0,0,1,2,3,6,12,24,48,Nn,

Here, we find that

Kn=Jn1+Jn2+Jn3+Jn4+Jn5
Ln=Jn1+Jn2+Jn3+Jn4
Mn=Jn1+Jn2+Jn3
Nn=Jn1+Jn2

Hence, we say that {Jn} is Cn type sequence, while {Kn} is Pn type sequence, and {Ln} is Qn type sequence, while {Mn} isRn type sequence, and {Nn} is Sn type sequence.

2.1 Linear sums and some properties

We have derived simple properties [2, 13, 14] of the sequences {Cn}, {Pn}, {Qn}, {Rn}, and{Sn}, expressing each of the terms C6,C7,C8,.,Cn+5C6, as the sum of its six preceding terms, as given in (4) adding both sides we obtained on

Simplification:

i=0nCi=15Cn+5Cn+32Cn+23Cn+1+CnC5C32C23C14C0E18

On using (4), (5), (7), (9), and (12), we get

i=0nC6i=i=06n1Ci+C0E19
i=0nC6i+2=i=06n+1Ci+P0E20
i=0nC6i+3=i=06n+2Ci+Q0E21
i=0nC6i+4=i=06n+3Ci+R0E22
i=0nC6i+5=i=06n+4Ci+S0E23
i=0nC6i+6=i=06n+5Ci+S1C0E24
i=0nC6i+5=i=06n+4Ci+R1C0E25
i=0nC6i+4=i=06n+3Ci+Q1C0E26
i=0nC6i+3=i=06n+2CiP1C0E27

2.2 Property of sequence {Jn2}

Theorem: For the sequence {Jn} we have,

JnJn+1Jn+2Jn+1Jn+2Jn+3Jn+2Jn+3Jn+4Jn+3Jn+4Jn+5Jn+4Jn+5Jn+6Jn+5Jn+6Jn+7Jn+3Jn+4Jn+5Jn+4Jn+5Jn+6Jn+5Jn+6Jn+7Jn+6Jn+7Jn+8Jn+7Jn+8Jn+9Jn+8Jn+9Jn+10=1n+1E28

Proof: Consider the determinant –

=111100010111000000001000000000100010

The value of this determinant is 1, we have

2=222111100222111000010001000000000100

Now, by mathematical induction,

n=Jn+1Kn+1Ln+1JnKnLnJn1Kn1Ln1Mn+1Nn+1JnMnNnJn1Mn1Nn1Jn2Jn2Kn2Ln2Jn3Kn3Ln3Jn4Kn4Ln4Mn2Nn2Jn3Mn3Nn3Jn4Mn4Nn4Jn5

Now, writing Mn+1=Jn+Jn1 the R.H.S. can be written as the sum of two determinants, one of which is zero, Therefore,

n=Jn+1Kn+1Ln+1JnKnLnJn1Kn1Ln1Mn+1Jn1JnMnJn2Jn1Mn1Jn3Jn2Jn2Kn2Ln2Jn3Kn3Ln3Jn4Kn4Ln4Mn2Jn4Jn3Mn3Jn5Jn4Mn4Jn6Jn5

Now, writing Mn+1=Jn+Jn1+Jn2, the R.H.S. can be written as the sum of three determinants, two of which are zero. Therefore,

n=Jn+1Kn+1Ln+1JnKnLnJn1Kn1Ln1Jn2Jn1JnJn3Jn2Jn1Jn4Jn3Jn2Jn2Kn2Ln2Jn3Kn3Ln3Jn4Kn4Ln4Jn5Jn4Jn3Jn6Jn5Jn4Jn7Jn6Jn5

Now, writing Ln+1=Jn+Jn1+Jn2+Jn3Ln + 1, the R.H.S. can be written as the sum of four determinants, three of which are zero. Therefore,

n=Jn+1Kn+1Jn3JnKnJn4Jn1Kn1Jn5Jn2Jn1JnJn3Jn2Jn1Jn4Jn3Jn2Jn2Kn2Jn6Jn3Kn3Jn7Jn4Kn4Jn8Jn5Jn4Jn3Jn6Jn5Jn4Jn7Jn6Jn5

Now, writing Kn+1=Jn+Jn1+Jn2+Jn3+Jn4 the R.H.S. can be written as the sum of five determinants, four of which are zero. Therefore,

n=Jn+1Jn4Jn3JnJn5Jn4Jn1Jn6Jn5Jn2Jn1JnJn3Jn2Jn1Jn4Jn3Jn2Jn2Jn7Jn6Jn3Jn8Jn7Jn4Jn8Jn8Jn5Jn4Jn3Jn6Jn5Jn4Jn7Jn6Jn5

On arranging, we get

n=Jn+1JnJn1JnJn1Jn2Jn1Jn2Jn3Jn2Jn3Jn4Jn3Jn4Jn5Jn4Jn5Jn6Jn2Jn3Jn4Jn3Jn4Jn5Jn4Jn5Jn6Jn5Jn6Jn7Jn6Jn7Jn8Jn7Jn8Jn9

Putting, n-9 = m or n = m + 9 and substituting all the Δ’s, we obtain,

1m+9=Jm+10Jm+9Jm+8Jm+9Jm+8Jm+7Jm+8Jm+7Jm+6Jm+7Jm+6Jm+5Jm+6Jm+5Jm+4Jm+5Jm+4Jm+3Jm+7Jm+6Jm+5Jm+6Jm+5Jm+4Jm+5Jm+4Jm+3Jm+4Jm+3Jm+2Jm+3Jm+2Jm+1Jm+2Jm+1Jm

Rearranging the determinant and replacing m with n we get the required result (28)

2.3 Generating matrix {Cn}

In this section, we will obtain some identities with the help of generating matrix, we consider the matrix,

T=111100010111000000001000000000100010E29

By mathematical induction, we can show that:

Tn=Jn+1Kn+1Ln+1JnKnLnJn1Kn1Ln1Mn+1Nn1JnMnNn2Jn1Mn1Nn3Jn2Jn2Kn2Ln2Jn3Kn3Ln3Jn4Kn4Ln4Mn2Nn4Jn3Mn3Nn5Jn4Mn4Nn6Jn5E30

where n5

and

CnCn1Cn2Cn3Cn4Cn5=TnC5C4C3C2C1C0,n5E31

On using (30) and (31), we get:

Cn+PCn+P1Cn+P2Cn+P3Cn+P4Cn+P5=Jn+1Kn+1Ln+1JnKnLnJn1Kn1Ln1Mn+1Nn1JnMnNn2Jn1Mn1Nn3Jn2Jn2Kn2Ln2Jn3Kn3Ln3Jn4Kn4Ln4Mn2Nn4Jn3Mn3Nn5Jn4Mn4Nn6Jn5CnCn1Cn2Cn3Cn4Cn5

From this we obtain:

Cn+P=JP+1Dn+KP+1Dn1+LP+1Dn2+MP+1Dn3+NP+1Dn4+JP+1Dn5E32

Let us now consider the matrix [W], which is the transpose of the matrix [T] in,

W=T=110101100000000100100100100010001000

It can be shown that the sequence

C4,P5,Q5,,R5,S5,C5.,Cn1,Pn,Qn,,Rn,Sn,CnE33

is generated by matrix [W]

CnPnQnRnSnCn1=Wn5C5P5Q5R5S5C4,n5E34

On using (33) and (34), we get

Cn+PPn+PQn+PRn+PSn+PCn+P=WPCnPnQnRnSnCn1=JP+1JPJP1KP+1KPKP1LP+1LPLP1JP2JP3JP4KP2KP3KP4LP2LP3LP4MP+1MPMP1NP+1NPNP1JPJP1JP2MP2MP3MP4NP2NP3NP4JP3JP4JP5CnPnQnRnSnCn1
Cn+P=JP+1Cn+JPPn+JP1Qn+JP2Rn+JP3Sn+JP4Cn1
Pn+P=KP+1Cn+KPPn+KP1Qn+KP2Rn+KP3Sn+KP4Cn1
Qn+P=LP+1Cn+LPPn+LP1Qn+LP2Rn+LP3Sn+LP4Cn1
Rn+P=MP+1Cn+MPPn+MP1Qn+MP2Rn+MP3Sn+MP4Cn1
Sn+P=NP+1Cn+NPPn+NP1Qn+NP2Rn+NP3Sn+NP4Cn1

Application:

We can introduce generalized Fibonacci n-step polynomials. Based on generalized Fibonacci n-step polynomials, we can define a new class of square matrix of order n and we can state a new coding theory called generalized Fibonacci n-step theory.

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3. Discussion

Mathematics has enormous potential for solving the various problems of daily life. The Fibonacci polynomials are a polynomial sequence that can be considered as generalization sequences worked upon by many mathematicians earlier like as Atanassov [11], Harne & Parihar [4], and Georgiev and Atanassov [8] in accordance with our findings. The chapter has wider acceptance for the fruitful study of various case studies as illustrated in the current citation, which is well supported by the earlier studies too.

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4. Conclusions

There are many known identities for the Fibonacci recursion relation. We define the sequence {Cn} and its four comparison sequences {Pn}, {Qn}, {Rn}, and {Sn}. We drive linear sum properties of comparison sequence. We also derive generating matrix for the sequence {Cn}.

References

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Written By

Manjeet Singh Teeth and Sanjay Harne

Submitted: 20 November 2022 Reviewed: 10 February 2023 Published: 21 April 2023