# Line slope calculator 3x-y=11

**Straight line given by points A[4; 1] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = 3x-11

**Canonical form of the line equation:**3x-y-11 = 0

**Parametric form of the line equation:**

x = t+4

y = 3t+1 ; t ∈ R

**Slope:**m = 3

**Slope angle of line: φ =**71°33'54″ = 1.249 rad

**X intercept:**x

_{0}= 3.6667

**Y intercept:**y

_{0}= q = -11

**Distance line from the origin:**d

_{0}= 3.4785

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; 3)

**Normal vector: n =**(3; -1)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**x+3y-12 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 24°37'25″ = 0.4298 rad**