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Perspective Chapter: Families of Seventh-Order KdV Equations Having Traveling Wave and Soliton Solutions

Written By

Alvaro Humberto Salas Salas

Submitted: 30 November 2023 Reviewed: 05 December 2023 Published: 03 May 2024

DOI: 10.5772/intechopen.1004789

Nonlinear Systems - Recent Advances and Application IntechOpen
Nonlinear Systems - Recent Advances and Application Edited by Peter Chen

From the Edited Volume

Nonlinear Systems - Recent Advances and Application [Working Title]

Dr. Peter Chen and Associate Prof. Muhammad Shahzad Nazir

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Abstract

In this paper, we consider the problem of finding traveling wave solutions to the generalized seventh-order KdV equation (KdV7). Solitons are non-linear waves that exhibit extremely unexpected and interesting behavior—solitary waves that propagate without deformation. We use different approaches in order to find one and multisoliton solutions. Soliton travels through liquid, solid, and gaseous media and even as electron waves through an electromagnetic field. Making use of a traveling wave transformation, we obtain a non-linear ode, which is solved using either hyperbolic or elliptic algorithm. We also use the Hirota method to get the bilinear form, and then we may obtain multisoliton solutions. In the end, we consider the forced KdV7.

Keywords

  • traveling wave solutions
  • KdV7
  • solitons
  • cnoidal waves
  • deformed sine-Gordon equation
  • Sawada-Kotera equation
  • Kaup–Kupershmidt equation
  • Ito equation
  • lLax equation

1. Introduction

One of the most notable achievements in the second half of the twentieth century, which also clearly illustrates the underlying unity of Mathematics and Nonlinear Physics, is the Theory of Solitons. Solitons are nonlinear waves exhibiting extremely unexpected and interesting behavior—solitary waves propagating without deformation.

The other waves, the nonlinear ones, are less familiar and are very different from the linear ones. A wave in the sea approaching the shore is a good example of a nonlinear wave. Note that the amplitude, wavelength, and speed vary as the wave advances, while in linear waves, these are constant. The distance between the crests decreases, the height of the waves increases as they perceive the bottom, and the speed changes. The upper part of the wave overtakes the lower part, falls on it, and the wave breaks. There are even more intricate phenomena such as two waves that intersect, interact in complicated and nonlinear ways, and give rise to three waves instead of two.

Now we come to solitons. During a horseback ride around Edinburgh, on the Union Canal in Hermiston, very close to the Riccarton campus of Heriot-Watt University, the Scottish engineer John Scott-Russell watched as a barge was towed along a narrow canal by two horses that pulled from land to obtain a more efficient design of boats.

A decisive step in the theory of integrable systems was the integration of the KdV equation. Thus, Gardner, Greene, Kruskal, and Miura observed that if we consider a potential u(x) for the stationary Schrödinger equation on the line, the corresponding scattering data are transformed extremely easily when the potential changes as long as u(x, t) satisfies the KdV equation. Therefore, given an initial condition u(x) for KdV, we can find the associated scattering data and determine its evolution immediately.

In this paper, we consider the following generalized seventh-order KdV equation (KdV7 for short):

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γuu5x+u7x=0.E1

This nonlinear evolution equation describes the behavior of physical phenomena such as shallow water waves and plasmas. Its conservation laws were determined to predict its complete integrability [1, 2]. In Ref. [3], Wazwaz obtained one and two soliton solutions for the following special cases:

  • The seventh-order Sawada-Kotera-Ito equation:

    ut+252u3ux+63ux3+378uxu2x+126u2u3x+63u2xu3x+42uxu4x+21uu5x+u7x=0.E2

  • The seventh-order Lax equation:

    ut+140u3ux+70ux3+280uxu2x+70u2u3x+70u2xu3x+42uxu4x+14uu5x+u7x=0.E3

  • The seventh-order Kaup-Kuperschmidt equation

ut+2016u3ux+630ux3+2268uxu2x+504u2u3x+252u2xu3x+147uxu4x+42uu5x+u7x=0.E4

These three cases of the seventh-order KdV equation are completely integrable. This means that each of these equations admits an infinite number of conservation laws, and as a result, each gives rise to N-soliton solutions. We aim to describe the families of these KdV7 that admit soliton and cnoidal wave solutions.

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2. Cnoidal wave solutions

Let

uxt=p+qxλt+ξ0g2g3.E5

Then

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γuu5x+u7x=12qg2g3+43[2ap32bg3q2cg2pq36γg2p24βg3q1440g32λ+(6ap2q2bg2q2cg2q2+24dp212αg2q36βg2q36γg2q4032g2)+6paq2+2cq+120γ+8dq2+2aq3+4bq2+6cq2+12dq2+72αq+120βq+360γq+201603],E5a

where =xλt+ξ0g2g3.

The system to be solved is

2ap32bg3q2cg2pq36γg224βg3q1440g3+2λ=0.6ap2q2bg2q2cg2q2+24dp212αg2q36βg2q4032g2=0.6apq2+12cpq+720γ+48dpq=0.2aq3+8bq2+12cq2+24dq2+144αq+240βq+40320=0.E6

We will have a solution for the following parameter values:

g2=6p2aq+4d2bq2+cq2+12αq+36βq+4032.g3=2ap3cg2pq36γg2+2λ2bq2+12βq+720.p=120γqaq+2c+8d.aq3+22b+3c+6dq2+243α+5βq+20160=0.E7

Example. Let

u01xt63.5567uxt3u10xt5089.7u10xt3+0.939611uxtu10xtu20xt+0.471886uxt2u30xt+0.0310296u20xtu30xt+0.626069u10xtu40xt+0.48252uxtu50xt+u70xt=0.E8

See Figure 1.

Figure 1.

uxt=0.480062+7.21261tx4.706535.33465i0.01396510.0000274235.

Let now

uxt=B+Ccn2ωxλt+ξ0m.E9

Then

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γuu5x+u7x=2Ccnsndn[λaB3ω2BcCω3+4B2dω3+2BcCmω38B2dmω3+8Cαω524Cmαω5+16Cm2αω5+8Cβω524Cmβω5+16Cm2βω516Bγω5+136Bmγω5136Bm2γω5+64ω72112mω7+5952m2ω73968m3ω7cn+ω3aB2C4BcCω2+4bC2ω2+2cC2ω28BCdω2+8BcCmω24bC2mω22cC2mω212B2dmω2+16BCdmω2+16Cαω488Cmαω4+88Cm2αω4+16Cβω4136Cmβω4+136Cm2βω4+16Cγω4+240Bmγω4136Cmγω4480Bm2γω4+136Cm2γω44032mω6+24192m2ω624192m3ω6cn3+ω3aBC24bC2ω24cC2ω24C2dω26BcCmω2+8bC2mω2+8cC2mω224BCdmω2+8C2dmω2+72Cmαω4144Cm2αω4+120Cmβω4240Cm2βω4+240Cmγω4+360Bm2γω4480Cm2γω420160m2ω6+40320m3ω6cn5+ωaC34bC2mω26cC2mω212C2dmω2+72Cm2αω4+120Cm2βω4+360Cm2γω420160m3ω6cn7].

Next, we equate to zero the coefficients of cnj to obtain an algebraic system of nonlinear equations. This system admits a solution under the condition

Δ1Δ2=0,E10

where

Δ1=17640a2+27aα2γ+90aαβγ+180aαγ2+75aβ2γ+300aβγ2840abγ+300aγ3126aαc210aβc1260aγc504aαd840aβd2520aγd+10b2γ2+14bc23αbγc5bβγc+10bγ2c+112bcd+224bd212αbγd20bβγd20bγ2d+14c33αγc25βγc2+126c2d+336cd215αγcd25βγcd30γ2cd+224d312αγd220βγd230γ2d2,andΔ2=28224a2+3aα3+3aα2β+63aα2γ63aαβ2+234aαβγ+297aαγ2135aβ3+135aβ2γ+168aαb+3192aβb+675aβγ23528abγ+405aγ3252aαc+588aβc2772acγ1008aαd3024aβd3024aγd+504b3+4α2b216αβb2+84αb2γ20β2b2+60βb2γ+360b2γ2+84b2c2016b2d70bc2+2α2bc12αβbc+48αbcγ+10β2bc120βbcγ+270bcγ2672bcd+2016bd26α2bd+12αβbd108αbγd+90β2bd180βbγd270bγ2d+7c32αβc2+3αc2γ+10β2c245βc2γ+45c2γ2+168c2d+1008cd23α2cd+6αβcd54αcγd+45β2cd90βcγd135cγ2d.

The Eqs. (2)(4) obey the condition in Eq. (10).

Solving the system we obtain the solutions as follows:

λ=ωaB3+8B2dmω24B2dω22BcCmω2+2BcCω2+16Bγω4+136m2ω4136Bγmω48αCω48βCω416αCm2ω416βCm2ω4+24αCmω4+24βCmω4+3968m3ω65952m2ω6+2112mω664ω6.B=42m1ω23aC22cCmω28Cdmω2+120γm2ω4(bC2+cC2+C2d18αCmω230βCmω260γCmω2+5040m2ω4).aC3+4bmω26cmω212dmω2C2+72αm2ω4+120βm2ω4+360γm2ω4C20160m3ω6=0.E11

C=2mω2λ=4ω(63B3+252B2mω2126B2ω2+336Bm2ω4336Bmω4+84Bω4+152m3ω6228m2ω6+108mω616ω6).uxt=B+Ccn2ωxλt+ξ0m).E12
B=432m1ω2,C=4mω2.λ=1283m2m+12m1ω7.uxt=B+Ccn2ωxλt+ξ0m).E13

C=2mω2.λ=4ω(35B3+140B2mω270B2ω2+196Bm2ω4196Bmω4+56Bω4+96m3ω6144m2ω6+80mω616ω6)uxt=B+2cn2ωxλt+ξ0m.E14

B=162m1ω2,C=mω22.λ=23m2m+12m1ω7.uxt=B+2cn2ωxλt+ξ0m.E15

  • Letting m = 1 in Eqs. (2)(4), we obtain solitonic solutions.

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3. Soliton solutions

3.1 First family

Let

A=252α+β+γ,w=k7.c=1126α+β+γα5β+4γbd.d=42aα+β+γ+1378α+β+γα5β+10γ+b3.E16

We make the transformation

u=Ax,xlog1+expkxwtE17

to obtain the soliton solution

usolitonxt=126k2α+β+γ1+coshkxk7tξ.E18

For a graphical illustration, see Figure 2.

Figure 2.

Soliton solution uxt=0.041+cosh0.0000128t0.2x to the Sawada-Kotera-Ito equation with k = 0.2.

We are interested in the existence of two soliton solutions. Let

uxt=252α+β+γx,xlog1+expθ1+expθ2+ρexpθ1+θ2.θ1=k1xk17tandθ2=k2xk27tE19

Making the choices

a=γ2β+2γβ33β2γ9βγ2+31γ349β5γ3b=βγβ36β2γ+15βγ223γ37β5γ2c=β49β3γ+25β2γ233βγ3+76γ47β5γ2d=2γβ35β2γ+2βγ2+17γ37β5γ2α=β24βγ+13γ2β5γρ=γ2k1k22k12k1k2+k222k1+extk222β2k12k222βγk1k2k12+4k1k2+k22+γ2k14+4k13k2+9k12k22+4k1k23+k24.E20

We obtain

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γu5x+u7x=βγβ2γβ3γRk1k2θ1θ2.

We conclude that the two soliton solutions exist for the parameter values in Eq. (20) under the condition

βγβ2γβ3γ=0.E21

We obtained the following result:

Theorem. The following families of KdV7 admit one and two soliton solutions for any p. The two soliton solutions have the form

u2solitonxt=252α+β+γxxlog1+expθ1+expθ2+ρexpθ1+θ2,E22

being

θ1=k1xk17t,θ2=k2xk27t.E23

  • First set:

a=15p3784,b=0,c=15p228,d=15p256,α=5p2,β=p,ρ=k1k22k12k1k2+k222k1+k22k12+k1k2+k222,γ=pE24

KdV7:

ut+15784p3u3ux+1528p2uuxu2x+1556p2u2u3x+52pu2xu3x+puxu4x+puu5x+u7x=0E25

An illustration with p = 1 is shown in Figure 3. The solution is

Figure 3.

Two soliton solution for p = 1.

uxt=14.e0.352855t+0.5x+27.44e0.278313t+0.7x+2.52676e0.2705t+1.2x+0.0975793e0.262688t+1.7x+0.0497854e0.188146t+1.9xe0.172521t+0.5x+e0.0979793t+0.7x+0.0035561e0.0901668t+1.2x+e0.180334t2E26

  • Second set:

a=4p3147,b=p27,c=6p27,d=2p27,α=3p,β=2p,ρ=k1k22k12k1k2+k22k1+k22k12+k1k2+k22,γ=pE27

KdV7:

ut+4147p3u3ux+17p2ux3+67p2uuxu2x+27p2u2u3x+3pu2xu3x+2puxu4x+puu5x+u7x=0E28

  • Third set:

a=5p398,b=5p214,c=10p27,d=5p214,α=5p,β=3p,ρ=k1k22k1+k22,γ=pE29

KdV7:

ut+598p3u3ux+514p2ux3+107p2uuxu2x+514p2u2u3x+5pu2xu3x+3puxu4x+puu5x+u7x=0E30

Now, our aim is to find three soliton solutions for the parameter values in Eq. (20). Assume the ansatz

uxt=252α+β+γxxlog1+j=13ηj+1i<j3ρi,jηiηj+ρ1,2,3η1η2η3,E31

where

ηj=expkjxkj7tforj=1,2,3.E32

We have:

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γuu5x+u7x=98β5γk1k2k1+k2(γ2k16γ2ρ1,2k166γ2k2k15+2βγk2k154γ2k2ρ1,2k15+2β2k22k14+18γ2k22k1412βγk22k148γ2k22ρ1,2k144β2k23k1326γ2k23k13+20βγk23k1310γ2k23ρ1,2k13+2β2k24k12+18γ2k24k1212βγk24k128γ2k24ρ1,2k126γ2k25k1+2βγk25k14γ2k25ρ1,2k1+γ2k26γ2k26ρ1,2)/γ4z1z2+98β5γk1k3k1+k3(γ2k16γ2ρ1,3k166γ2k3k15+2βγk3k154γ2k3ρ1,3k15+2β2k32k14+18γ2k32k1412βγk32k148γ2k32ρ1,3k144β2k33k1326γ2k33k13+20βγk33k1310γ2k33ρ1,3k13+2β2k34k12+18γ2k34k1212βγk34k128γ2k34ρ1,3k126γ2k35k1+2βγk35k14γ2k35ρ1,3k1+γ2k36γ2k36ρ1,3)/γ4z1z3+98β5γk2k3k2+k3(γ2k26γ2ρ2,3k266γ2k3k25+2βγk3k254γ2k3ρ2,3k25+2β2k32k24+18γ2k32k2412βγk32k248γ2k32ρ2,3k244β2k33k2326γ2k33k23+20βγk33k2310γ2k33ρ2,3k23+2β2k34k22+18γ2k34k2212βγk34k228γ2k34ρ2,3k226γ2k35k2+2βγk35k24γ2k35ρ2,3k2+γ2k36γ2k36ρ2,3)/γ4z2z3+h.o.t

Equating to zero the coefficients of z1z2, z1z3, and z2z3 and solving the resulting system of algebraic equations we obtain

ρ1,2=k1k222β2k22k12+2βγk2k138βγk22k12+2βγk23k1+γ2k144γ2k2k13+9γ2k22k124γ2k23k1+γ2k24γ2k1+k22k12+k2k1+k222.ρ1,3=k1k322β2k32k12+2βγk3k138βγk32k12+2βγk33k1+γ2k144γ2k3k13+9γ2k32k124γ2k33k1+γ2k34γ2k1+k32k12+k3k1+k322.ρ2,3=k2k322β2k32k22+2βγk3k238βγk32k22+2βγk33k2+γ2k244γ2k3k23+9γ2k32k224γ2k33k2+γ2k34γ2k2+k32k22+k3k2+k322.E33

Next, we equate to zero the coefficient of z1z2z3 in order to obtain the value for ρ1,2,3. It is given as follows.

  • For β=γ:

ρ1,2,3=P1/Q1,whereP1=γ4k2k12k2k32k3k12k1+k2+k3(k24k113+k34k1132k2k33k113+3k22k32k1132k23k3k113+k25k112+k35k112k2k34k112+k22k33k112+k23k32k112k24k3k112+2k26k111+2k36k1113k2k35k111+6k22k34k1115k23k33k111+6k24k32k1113k25k3k111+2k27k110+2k37k1104k2k36k11010k22k35k11018k23k34k11018k24k33k11010k25k32k1104k26k3k110+3k28k19+3k38k196k2k37k197k22k36k1938k23k35k1926k24k34k1938k25k33k197k26k32k196k27k3k19+3k29k18+3k39k183k2k38k187k22k37k1835k23k36k1858k24k35k1858k25k34k1835k26k33k187k27k32k183k28k3k18+2k210k17+2k310k176k2k39k177k22k38k1741k23k37k1760k24k36k1799k25k35k1760k26k34k1741k27k33k177k28k32k176k29k3k17+2k211k16+2k311k164k2k310k167k22k39k1635k23k38k1660k24k37k1692k25k36k1692k26k35k1660k27k34k1635k28k33k167k29k32k164k210k3k16+k212k15+k312k153k2k311k1510k22k310k1538k23k39k1558k24k38k1599k25k37k1592k26k36k1599k27k35k1558k28k34k1538k29k33k1510k210k32k153k211k3k15+k213k14+k313k14k2k312k14+6k22k311k1418k23k310k1426k24k39k1458k25k38k1460k26k37k1460k27k36k1458k28k35k1426k29k34k1418k210k33k14+6k211k32k14k212k3k142k2k313k13+k22k312k135k23k311k1318k24k310k1338k25k39k1335k26k38k1341k27k37k1335k28k36k1338k29k35k1318k210k34k135k211k33k13+k212k32k132k213k3k13+3k22k313k12+k23k312k12+6k24k311k1210k25k310k127k26k39k127k27k38k127k28k37k127k29k36k1210k210k35k12+6k211k34k12+k212k33k12+3k213k32k122k23k313k1k24k312k13k25k311k14k26k310k16k27k39k13k28k38k16k29k37k14k210k36k13k211k35k1k212k34k12k213k33k1+k24k313+k25k312+2k26k311+2k27k310+3k28k39+3k29k38+2k210k37+2k211k36+k212k35+k213k34),

and

Q1=γ4k1+k22k12+k2k1+k222k1+k32k2+k32k1+k2+k32k12+k3k1+k322k22+k3k2+k322(k14+2k2k13+2k3k13+3k22k12+3k32k12+5k2k3k12+2k23k1+2k33k1+5k2k32k1+5k22k3k1+k24+k34+2k2k33+3k22k32+2k23k3).

  • For β=2γ:

ρ1,2,3=P2/Q2,whereP2=γ4k2k12k12k2k1+k22k12+k2k1+k22k2k32k3k12k1+k2+k32k12k3k1+k32k12+k3k1+k32k22k3k2+k32k22+k3k2+k32(k14+2k2k13+2k3k13+3k22k12+3k32k12+5k2k3k12+2k23k1+2k33k1+5k2k32k1+5k22k3k1+k24+k34+2k2k33+3k22k32+2k23k3),

and

Q2=γ4k1+k22k12+k2k1+k222k1+k32k2+k32k1+k2+k32k12+k3k1+k322k22+k3k2+k322(k14+2k2k13+2k3k13+3k22k12+3k32k12+5k2k3k12+2k23k1+2k33k1+5k2k32k1+5k22k3k1+k24+k34+2k2k33+3k22k32+2k23k3).

  • For β=3γ:

ρ1,2,3=P3/Q3,whereP3=γ4k2k12k12k2k1+k22k12+k2k1+k22k2k32k3k12k1+k2+k32k12k3k1+k32k12+k3k1+k32k22k3k2+k32k22+k3k2+k32(k14+2k2k13+2k3k13+3k22k12+3k32k12+5k2k3k12+2k23k1+2k33k1+5k2k32k1+5k22k3k1+k24+k34+2k2k33+3k22k32+2k23k3),

and

Q3=γ4k1+k22k12+k2k1+k222k1+k32k2+k32k1+k2+k32k12+k3k1+k322k22+k3k2+k322(k14+2k2k13+2k3k13+3k22k12+3k32k12+5k2k3k12+2k23k1+2k33k1+5k2k32k1+5k22k3k1+k24+k34+2k2k33+3k22k32+2k23k3).

We have three soliton solutions only when β=2γ or β=3γ. Thus, the KdV7 has two soliton solutions for the parameter values in Eq. (20), but it does not have three soliton solutions for γ=β..

3.2 Second family

Let

a=57α+5β6γα+β+γ27938.b=163α+β+γ36α+35β+10γ.c=163α+β+γ37α+35β+15γ.d=1126α+β+γα+5β+30γ.E34

We make the transformation

uxt=126α+β+γx,xlog1+expkxk7t+ρexp2kx2k7tE35

to obtain the soliton solution

usolitonxt=504k2ek7t+kxα+β+γ2ek7t+ekx2forρ=14.E36

A cnoidal wave solution is

ucnoidalxt=p+12m±m2m+1pm1cn2qα+β+γ252mxλt+ξ0m,E37

where

λ=1500094m3[α+β+γ2(2205αm3p3+1575βm3p31890γm3p3126αm3p2q630βm3p2q3780γm3p2q2331αm3pq22205βm3pq22016γm3pq2+2αm3q3+2βm3q3124γm3q3+63αm2p2q+315βm2p2q+1890γm2p2q+2331αm2pq2+2205βm2pq2+2016γm2pq23αm2q33βm2q3+186γm2q3126γmpq23αmq33βmq366γmq3+2αq3+2βq3+2γq3)].

3.3 Third family

Let

a=8α+β+γ24α10β+25γ453789.b=188216α2+22αβ23αγ+38β2+31βγ7γ2.c=8α2+2αβ+107αγ6β2+93βγ+99γ21029.d=22α2+4αβ31αγ+2β231βγ33γ21029.E38

We make the transformation

uxt=4412α+β+γx,xlog1+expkxk7t+ρexp2kx2k7tE39

to obtain the soliton solution

usolitonxt=3528k216ek7tkx+ekxk7t+4α+β+γ16ek7tkx+ekxk7t+162forρ=116.E40

A cnoidal wave solution is

uxt=p+3mp12mcn22pα+β+γ14712mxλt+ξ0m,E41

where

λ=4m2m+1p348α50β99γα+β+γ231765232m12.E42

Let us investigate the existence of two soliton solutions in the ansatz form

uxt=4412α+β+γxxlog(1+expθ1+expθ2+116exp2θ1+exp2θ2+ρexpθ1+2θ2+exp2θ1+θ2+κexpθ1+θ2+ρ2exp2θ1+2θ2),whereθ1=k1xk17tandθ2=k2xk27t.

We have three soliton solutions for the following choices:

a=4γ3147,b=5γ214,c=9γ27,d=2γ27,α=6γ,β=7γ2.E43
κ=2k14k22k12+2k242k1+k22k12+k2k1+k22,ρ=k1k22k12k2k1+k2216k1+k22k12+k2k1+k22E44

Letting γ=42 gives the Kaup–Kuperschmidt seventh-order equation:

ut+2016u3ux+630ux3+2268uxu2x+504u2u3x+252u2xu3x+147uxu4x+42uu5x+u7x=0.E45

3.4 Three soliton solutions

The three soliton solutions have the form

u3solitonxt=1/2xxlog1+i,j,l=02ρi,j,lexpik1xk17t+jk2xk27t+lk3xk37t,E46

where ρi,j,l=1 when i + j + l = 1. The parameter values are obtained as follows. First, we set

k1xk17t=logz1,k2xk27t=logz2andk3xk37t=logz3E47

to get

ut+2016u3ux+630ux3+2268uxu2x+504u2u3x+252u2xu3x+147uxu4x+42u5x+u7x=Ψz1z2z3.

Next, we solve the equation

i+j+lz1iz2jlz3Ψz1z2z3z1=z2=z3=0=0E48

for ρi,j,l. The parameter values are:

ρ0,0,2=116,ρ0,1,1=2k24k32k22+2k342k2+k32k22+k3k2+k32,ρ0,1,2=k2k32k22k3k2+k3216k2+k32k22+k3k2+k32.
ρ0,2,0=116,ρ0,2,1=k2k32k22k3k2+k3216k2+k32k22+k3k2+k32,ρ1,0,1=2k14k32k12+2k342k1+k32k12+k3k1+k32.
ρ1,0,2=k1k32k12k3k1+k3216k1+k32k12+k3k1+k32,ρ1,1,0=2k14k22k12+2k242k1+k22k12+k2k1+k22,ρ1,2,0=k1k22k12k2k1+k2216k1+k22k12+k2k1+k22.
ρ2,0,0=116,ρ2,0,1=k1k32k12k3k1+k3216k1+k32k12+k3k1+k32,ρ2,1,0=k1k22k12k2k1+k2216k1+k22k12+k2k1+k22.
ρ0,2,2=k2k34k22k3k2+k322256k2+k34k22+k3k2+k322.
ρ1,1,1=14k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32
×[4k24k18+4k34k182k22k32k182k26k162k36k16k22k34k16k24k32k16+4k28k14+4k38k14k22k36k146k24k34k14k26k32k142k22k38k12k24k36k12k26k34k122k28k32k12+4k24k382k26k36+4k28k34].
ρ1,1,2=2k14k22k12+2k24k1k32k2k32k12k3k1+k32k22k3k2+k3232k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32.
ρ1,2,1=k1k22k12k2k1+k22k2k32k22k3k2+k322k14k32k12+2k3432k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32.
ρ1,2,2=k1k22k12k2k1+k22k1k32k2k34k12k3k1+k32k22k3k2+k322256k1+k22k12+k2k1+k22k1+k32k2+k34k12+k3k1+k32k22+k3k2+k322.
ρ2,0,2=k1k34k12k3k1+k322256k1+k34k12+k3k1+k322.
ρ2,1,1=k1k22k12k2k1+k22k1k32k12k3k1+k322k24k32k22+2k3432k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32.
ρ2,1,2=k1k22k12k2k1+k22k1k34k2k32k12k3k1+k322k22k3k2+k32256k1+k22k12+k2k1+k22k1+k34k2+k32k12+k3k1+k322k22+k3k2+k32.
ρ2,2,0=k1k24k12k2k1+k222256k1+k24k12+k2k1+k222.
ρ2,2,1=k1k24k12k2k1+k222k1k32k2k32k12k3k1+k32k22k3k2+k32256k1+k24k12+k2k1+k222k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32.
ρ2,2,2=k1k24k12k2k1+k222k1k34k2k34k12k3k1+k322k22k3k2+k3224096k1+k24k12+k2k1+k222k1+k34k2+k34k12+k3k1+k322k22+k3k2+k322.

3.5 Four soliton solutions

The four soliton solutions have the form uxt=1/2xxlogfxt, where

fxt=i1=02i2=02i3=02i4=02Bi1i2i3i4z1i1z2i2z3i3z4i4,zj=expkjxkj7xforanyjE49

The 76 coefficients Bi1i2i3i4 are given by

B0002=116,B0011=2k34k42k32+2k442k3+k42k32+k4k3+k42.
B0012=k3k42k32k4k3+k4216k3+k42k32+k4k3+k42,B0020=116.
B0021=k3k42k32k4k3+k4216k3+k42k32+k4k3+k42.B0022=k3k44k32k4k3+k422256k3+k44k32+k4k3+k422.B0101=2k24k42k22+2k442k2+k42k22+k4k2+k42.B0102=k2k42k22k4k2+k4216k2+k42k22+k4k2+k42.B0110=2k24k32k22+2k342k2+k32k22+k3k2+k32.
B0111=[4k34k28+4k44k282k32k42k282k36k262k46k26k32k44k26k34k42k26+4k38k24+4k48k24k32k46k246k34k44k24k36k42k242k32k48k22k34k46k22k36k44k222k38k42k22+4k34k482k36k46+4k38k44]/[4k2+k32k22+k3k2+k32k2+k42k3+k42k22+k4k2+k42k32+k4k3+k42].B0112=2k24k32k22+2k34k2k42k3k42k22k4k2+k42k32k4k3+k4232k2+k32k22+k3k2+k32k2+k42k3+k42k22+k4k2+k42k32+k4k3+k42B0120=k2k32k22k3k2+k3216k2+k32k22+k3k2+k32B0121=k2k32k22k3k2+k32k3k42k32k4k3+k422k24k42k22+2k4432k2+k32k22+k3k2+k32k2+k42k3+k42k22+k4k2+k42k32+k4k3+k42
B0122=k2k32k22k3k2+k32k2k42k3k44k22k4k2+k42k32k4k3+k422256k2+k32k22+k3k2+k32k2+k42k3+k44k22+k4k2+k42k32+k4k3+k422B0200=116,B0201=k2k42k22k4k2+k4216k2+k42k22+k4k2+k42B0202=k2k44k22k4k2+k422256k2+k44k22+k4k2+k422,B0210=k2k32k22k3k2+k3216k2+k32k22+k3k2+k32.B0211=k2k32k22k3k2+k32k2k42k22k4k2+k422k34k42k32+2k4432k2+k32k22+k3k2+k32k2+k42k3+k42k22+k4k2+k42k32+k4k3+k42.B0212=k2k32k22k3k2+k32k2k44k3k42k22k4k2+k422k32k4k3+k42256k2+k32k22+k3k2+k32k2+k44k3+k42k22+k4k2+k422k32+k4k3+k42.B0220=k2k34k22k3k2+k322256k2+k34k22+k3k2+k322B0221=k2k34k22k3k2+k322k2k42k3k42k22k4k2+k42k32k4k3+k42256k2+k34k22+k3k2+k322k2+k42k3+k42k22+k4k2+k42k32+k4k3+k42.B0222=k2k34k22k3k2+k322k2k44k3k44k22k4k2+k422k32k4k3+k4224096k2+k34k22+k3k2+k322k2+k44k3+k44k22+k4k2+k422k32+k4k3+k422.B1001=2k14k42k12+2k442k1+k42k12+k4k1+k42,B1002=k1k42k12k4k1+k4216k1+k42k12+k4k1+k42.B1010=2k14k32k12+2k342k1+k32k12+k3k1+k32
B1011=[4k34k18+4k44k182k32k42k182k36k162k46k16k32k44k16k34k42k16+4k38k14+4k48k14k32k46k146k34k44k14k36k42k142k32k48k12k34k46k12k36k44k122k38k42k12+4k34k482k36k46+4k38k44]/[4k1+k32k12+k3k1+k32k1+k42k3+k42k12+k4k1+k42k32+k4k3+k42].
B1012=2k14k32k12+2k34k1k42k3k42k12k4k1+k42k32k4k3+k4232k1+k32k12+k3k1+k32k1+k42k3+k42k12+k4k1+k42k32+k4k3+k42B1020=k1k32k12k3k1+k3216k1+k32k12+k3k1+k32B1021=k1k32k12k3k1+k32k3k42k32k4k3+k422k14k42k12+2k4432k1+k32k12+k3k1+k32k1+k42k3+k42k12+k4k1+k42k32+k4k3+k42
B1022=k1k32k12k3k1+k32k1k42k3k44k12k4k1+k42k32k4k3+k422256k1+k32k12+k3k1+k32k1+k42k3+k44k12+k4k1+k42k32+k4k3+k422B1100=2k14k22k12+2k242k1+k22k12+k2k1+k22
B1101=[4k24k18+4k44k182k22k42k182k26k162k46k16k22k44k16k24k42k16+4k28k14+4k48k14k22k46k146k24k44k14k26k42k142k22k48k12k24k46k12k26k44k122k28k42k12+4k24k482k26k46+4k28k44]/[4k1+k22k12+k2k1+k22k1+k42k2+k42k12+k4k1+k42k22+k4k2+k42].
B1102=2k14k22k12+2k24k1k42k2k42k12k4k1+k42k22k4k2+k4232k1+k22k12+k2k1+k22k1+k42k2+k42k12+k4k1+k42k22+k4k2+k42B1120=2k14k22k12+2k24k1k32k2k32k12k3k1+k32k22k3k2+k3232k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32
B1121=k1k32k2k32k12k3k1+k32k22k3k2+k32k3k42k32k4k3+k42(4k24k18+4k44k182k22k42k182k26k162k46k16k22k44k16k24k42k16+4k28k14+4k48k14+k22k46k146k24k44k14k26k42k142k22k48k12k24k46k12k26k44k122k28k42k12+4k24k482k26k46+4k28k44)/[64k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B1122=2k14k22k12+2k24k1k32k2k32k12k3k1+k32k22k3k2+k32k1k42k2k42k3k44k12k4k1+k42k22k4k2+k42k32k4k3+k422/[512k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k42k3+k44k12+k4k1+k42k22+k4k2+k42k32+k4k3+k422].
B1200=k1k22k12k2k1+k2216k1+k22k12+k2k1+k22B1201=k1k22k12k2k1+k22k2k42k22k4k2+k422k14k42k12+2k4432k1+k22k12+k2k1+k22k1+k42k2+k42k12+k4k1+k42k22+k4k2+k42B1202=k1k22k12k2k1+k22k1k42k2k44k12k4k1+k42k22k4k2+k422256k1+k22k12+k2k1+k22k1+k42k2+k44k12+k4k1+k42k22+k4k2+k422B1210=k1=k22k12k2k1+k22k2k32k22k3k2+k322k14k32k12+2k3432k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32
B1211=k1k22k12k2k1+k22k2k32k22k3k2+k32k2k42k22k4k2+k424k34k18+4k44k182k32k42k182k36k162k46k16k32k44k16k34k42k16+4k38k14+4k48k14k32k46k146k34k44k14k36k42k142k32k48k12k34k46k12k36k44k122k38k42k12+4k34k482k36k46+4k38k44/[64k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B1212=[k1k22k12k2k1+k22k2k32k22k3k2+k322k14k32k12+2k34k1k42k2k44k3k42k12k4k1+k42k22k4k2+k422k32k4k3+k42]/[512k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k44k3+k42k12+k4k1+k42k22+k4k2+k422k32+k4k3+k42].
B1220=k1k22k12k2k1+k22k1k32k2k34k12k3k1+k32k22k3k2+k322256k1+k22k12+k2k1+k22k1+k32k2+k34k12+k3k1+k32k22+k3k2+k322.
B1221=[k1k22k12k2k1+k22k1k32k2k34k12k3k1+k32k22k3k2+k322k2k42k3k42k22k4k2+k42k32k4k3+k422k14k42k12+2k44]/[512k1+k22k12+k2k1+k22k1+k32k2+k34k12+k3k1+k32k22+k3k2+k322k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B1222=k1k22k12k2k1+k22k1k32k2k34k12k3k1+k32k22k3k2+k322k1k42k2k44k3k44k12k4k1+k42k22k4k2+k422k32k4k3+k422/[4096k1+k22k12+k2k1+k22k1+k32k2+k34k12+k3k1+k32k22+k3k2+k322k1+k42k2+k44k3+k44k12+k4k1+k42k22+k4k2+k422k32+k4k3+k422].
B2000=116,B2001=k1k42k12k4k1+k4216k1+k42k12+k4k1+k42,B2002=k1k44k12k4k1+k422256k1+k44k12+k4k1+k422.
B2010=k1k32k12k3k1+k3216k1+k32k12+k3k1+k32.
B2011=k1k32k12k3k1+k32k1k42k12k4k1+k422k34k42k32+2k4432k1+k32k12+k3k1+k32k1+k42k3+k42k12+k4k1+k42k32+k4k3+k42.B2012=k1k32k12k3k1+k32k1k44k3k42k12k4k1+k422k32k4k3+k42256k1+k32k12+k3k1+k32k1+k44k3+k42k12+k4k1+k422k32+k4k3+k42.B2020=k1k34k12k3k1+k322256k1+k34k12+k3k1+k322.B2021=k1k34k12k3k1+k322k1k42k3k42k12k4k1+k42k32k4k3+k42256k1+k34k12+k3k1+k322k1+k42k3+k42k12+k4k1+k42k32+k4k3+k42.B2022=k1k34k12k3k1+k322k1k44k3k44k12k4k1+k422k32k4k3+k4224096k1+k34k12+k3k1+k322k1+k44k3+k44k12+k4k1+k422k32+k4k3+k422.B2100=k1k22k12k2k1+k2216k1+k22k12+k2k1+k22.B2101=k1k22k12k2k1+k22k1k42k12k4k1+k422k24k42k22+2k4432k1+k22k12+k2k1+k22k1+k42k2+k42k12+k4k1+k42k22+k4k2+k42.B2102=k1k22k12k2k1+k22k1k44k2k42k12k4k1+k422k22k4k2+k42256k1+k22k12+k2k1+k22k1+k44k2+k42k12+k4k1+k422k22+k4k2+k42.B2110=k1k22k12k2k1+k22k1k32k12k3k1+k322k24k32k22+2k3432k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32.
B2111=[k1k22k12k2k1+k22k1k32k12k3k1+k32k1k42k12k4k1+k42(4k34k28+4k44k282k32k42k282k36k262k46k26k32k44k26k34k42k26+4k38k24+4k48k24k32k46k246k34k44k24k36k42k242k32k48k22k34k46k22k36k44k222k38k42k22+4k34k482k36k46+4k38k44)]/[64k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B2112=[k1k22k12k2k1+k22k1k32k12k3k1+k322k24k32k22+2k34k1k44k2k42k3k42k12k4k1+k422k22k4k2+k42k32k4k3+k42]/[512k1+k22k12+k2k1+k22k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k44k2+k42k3+k42k12+k4k1+k422k22+k4k2+k42k32+k4k3+k42].
B2120=k1k22k12k2k1+k22k1k34k2k32k12k3k1+k322k22k3k2+k32256k1+k22k12+k2k1+k22k1+k34k2+k32k12+k3k1+k322k22+k3k2+k32.
B2121=[k1k22k12k2k1+k22k1k34k2k32k12k3k1+k322k22k3k2+k32k1k42k3k42k12k4k1+k42k32k4k3+k422k24k42k22+2k44]/[512k1+k22k12+k2k1+k22k1+k34k2+k32k12+k3k1+k322k22+k3k2+k32k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B2122=[k1k22k12k2k1+k22k1k34k2k32k12k3k1+k322k22k3k2+k32k1k44k2k42k3k44k12k4k1+k422k22k4k2+k42k32k4k3+k422]/[4096k1+k22k12+k2k1+k22k1+k34k2+k32k12+k3k1+k322k22+k3k2+k32k1+k44k2+k42k3+k44k12+k4k1+k422k22+k4k2+k42k32+k4k3+k422].
B2200=k1k24k12k2k1+k222256k1+k24k12+k2k1+k222.
B2201=k1k24k12k2k1+k222k1k42k2k42k12k4k1+k42k22k4k2+k42256k1+k24k12+k2k1+k222k1+k42k2+k42k12+k4k1+k42k22+k4k2+k42B2202=k1k24k12k2k1+k222k1k44k2k44k12k4k1+k422k22k4k2+k4224096k1+k24k12+k2k1+k222k1+k44k2+k44k12+k4k1+k422k22+k4k2+k422B2210=k1k24k12k2k1+k222k1k32k2k32k12k3k1+k32k22k3k2+k32256k1+k24k12+k2k1+k222k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32
B2211=[k1k24k12k2k1+k222k1k32k2k32k12k3k1+k32k22k3k2+k32k1k42k2k42k12k4k1+k42k22k4k2+k422k34k42k32+2k44]/[512k1+k24k12+k2k1+k222k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B2212=[k1k24k12k2k1+k222k1k32k2k32k12k3k1+k32k22k3k2+k32k1k44k2k44k3k42k12k4k1+k422k22k4k2+k422k32k4k3+k42]/[4096k1+k24k12+k2k1+k222k1+k32k2+k32k12+k3k1+k32k22+k3k2+k32k1+k44k2+k44k3+k42k12+k4k1+k422k22+k4k2+k422k32+k4k3+k42].
B2220=k1k24k12k2k1+k222k1k34k2k34k12k3k1+k322k22k3k2+k3224096k1+k24k12+k2k1+k222k1+k34k2+k34k12+k3k1+k322k22+k3k2+k322.
B2221=[k1k24k12k2k1+k222k1k34k2k34k12k3k1+k322k22k3k2+k322k1k42k2k42k3k42k12k4k1+k42k22k4k2+k42k32k4k3+k42]/[4096k1+k24k12+k2k1+k222k1+k34k2+k34k12+k3k1+k322k22+k3k2+k322k1+k42k2+k42k3+k42k12+k4k1+k42k22+k4k2+k42k32+k4k3+k42].
B2222=[k1k24k12k2k1+k222k1k34k2k34k12k3k1+k322k22k3k2+k322k1k44k2k44k3k44k12k4k1+k422k22k4k2+k422k32k4k3+k422]/[65536k1+k24k12+k2k1+k222k1+k34k2+k34k12+k3k1+k322k22+k3k2+k322k1+k44k2+k44k3+k44k12+k4k1+k422k22+k4k2+k422k32+k4k3+k422].

For a graphical illustration, see Figure 4.

Figure 4.

Four soliton solution:k1=0.489591k2=0.68479k3=0.104676k4=0.733527.

3.6 N-soliton solutions

The N-soliton solutions have the form uxt=1/2xxlogfxt, where

fxt=i1,i2,,iN=02Bi1i2iNΠj=1Nzjij,zj=expkjxkj7xforanyjE50

In order to find the unknown coefficients Bi1i2iN, we define

Ψz1z2zN=ut+2016u3ux+630ux3+2268uxu2x+504u2u3x+252u2xu3x+147uxu4x+42uu5x+u7x.

The number Bi1i2iN is obtained from the equation

i1+i2++iNz1i1z2i2zNinΨ0,0,00=0E51
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4. Bilinearization

Let us consider the case when d=c/2b. The family to be considered is

ut+au3ux+bux3+cuuxu2x+c/2bu2u3x+αu2xu3x+βuxu4x+γuu5x+u7x=0.E52

Let

uxt=Axxfxt.E53

Plugging the ansatz in Eq. (53) into Eq. (52) and integrating once with respect to x, taking a zero integration constant gives

3fx(8f4(4Afxxx2Ab+5β5γD2xff+2f(AγβfxxxxxxD2xff+2f(D8xff+Dxtff))+Aαβ+γ140D4xff2+Aβ+γ112D2xffD6xff)+D2xff4aA3+6A12α+4Ab2Ac+3β+77γ20160+4f2D2xff2D4xffA2c2b3A4α+β+19γ+3360)48Af2fx4fxxx4Ab+15γβD2xff24Af2fx2fxxx(34Ab15β+15γD2xff2+10f2βγD4xff)+8Afx3(2f2βγ(f220fxxx22ffxxxxxx+D6xff+15D2xffD4xff)+93Ab+20γβD2xff3)+4Af2βγfxxx(4f420fxxx2+D6xff+8f5fxxxxxx45D2xff3+30f2D2xffD4xff)+288Af2βγfx6fxxx+96Afx7Ab+12γβD2xff+48Afx5(32Ab15β+15γD2xff2+5f2βγD4xff)+288Aγβfx9=0.

The choices

α=5γ2β=γa=15γ3784b=0c=15γ228E54

will give the following bilinear form

Dxt1ff+Dx8ff=0E55

This corresponds to the KdV7 A=2γ=28

ut+420u3ux+420uxu2x+210u2u3x+70u2xu3x+28uxu4x+28uu5x+u7x=0.E56

This KdV7 admits one and two soliton solutions. However, it does not have three solitons solutions despite the fact that it admits bilinear form.

One soliton solution: uxt=2xxlog1+expk1xk17t..

Two soliton solution: uxt=2xxlog1+expk1xk17t+expk2xk27t+A12expk1xk17texpk2xk27t,

where

A1,2=k2k12k12k2k1+k222k1+k22k12+k2k1+k222.E57

Breather: uxt=2xxlogpekxλt+qeλtkx+rsinκxμt, where

λ=k7κ6+k621κ2k4+35κ4k2.μ=κκ6+7k635κ2k4+21κ4k2.p=κ2r23κ2k224k2qκ23k22.E58

Let us consider a more general than Eq. (56) KdV7

ut+420u3ux+420uuxuxx+210u2uxxx+70uxxuxxx+28uxuxxxx+28uuxxxxx+u7x+6puux+45qu2ux+15quxuxx+puxxx+15quuxxx+quu5x+u7x=0.

This KdV7 admits the bilinear form

Dxt1ff+pDx4ff+qDx6ff+Dx8ff=0.E59

The one soliton solutions are

uxt=k2ek3tk4+k2q+p+kxek3tk4+k2q+p+ekx2.

The two soliton solutions are

uxt=xxlog1+expk1xw1t+expk2xw2t+A1,2expk1xw1texpk2xw2t,

where w1=k13p+k15q+k17,w2=k23p+k25q+k27, and

A1,2=k1k225k12q5k2k1q+5k22q+7k1414k2k13+21k22k1214k23k1+7k24+3pk1+k225k12q+5k2k1q+5k22q+7k14+14k2k13+21k22k12+14k23k1+7k24+3p.E60

On the other hand, direct calculations show that the KdV7

ut+3α5β2β+γ21176u3ux+156βγ2β+γux3+1282β+γ2α3β+3γuuxuxx+1282β+γα2β+2γu2uxxx+αuxxuxxx+βuxuxxxx+γuuxxxxx+uxxxxxxx=0

may be written in the following Hirota’s bilinear form [4]:

2Dxtff+7βγ2β+γDx4fg3β3γ2β+γDx4ff+146α8β7γ2β+γDx8ff+146α8β7γ2β+γgg=0.Dx4fffg=0.uxt=Axxlogfxt,A=168γ+2β.E61

The seventh-order Kaup-Kuperschmidt Eq. (4) belongs to this class A=1/2. Using the obtained bilinear form, we may obtain all the results we presented in previous sections (for the special case d=c/2b).

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5. Forced KdV7

The forced KdV7 is written as

ut+au3ux+bux3+cuuxu2x+du2u3x+αu2xu3x+βuxu4x+γu5x+u7x=ft.E62

The forced Sawada-Kotera-Ito Eq. (2) and the forced Lax Eq. (3) admit the exact solution.

ut+252u3ux+63ux3+378uxu2x+126u2u3x+63u2xu3x+42uxu4x+21uu5x+u7x=ft.

Exact solution:

uxt=B+2sech2xλt+Ft,E63

where

λt=463B3+189B2Ft+126B2+189BFt2+252BFt+84B+63Ft3+126Ft2+84Ft+16dt.E64

and

Ft=ft.E65
ut+140u3ux+70ux3+280uxu2x+70u2u3x+70u2xu3x+42uxu4x+14uu5x+u7x=0.

  • Exact solution:

uxt=B+2sech2xλt+Ft,E66

where

λt=435B3+105B2Ft+70B2+105BFt2+140BFt+56B+35Ft3+70Ft2+56Ft+16dt.E67

and

Ft=ft.E68

For other parameter values, we obtained the following result:

If α+β+γ0 and

a=163dα+β+γb=1126α2+4αβ11αγ+5β25βγ10γ2+126dc=1215αγ+5βγ+5γ242dE69

then the forced KdV7 in Eq. (2) admits the exact solution

uxt=B+252α+β+γsech2xλt+Ft,E70

where

λt=163Ft3αB2d+3βB2d+3B2γd+504Bd+1008γ+Ft23αBd+3βBd+3Bγd+252d+Ft3αd+βd+γddt+163tαB3d+βB3d+B3γd+252B2d+1008+4032,Ft=ft.

See also [5].

References

  1. 1. Yao R-X, Li Z-B. Conservation Laws and new exact solutions for the generalized seventh order KdV equation. Chaos, Solitons and Fractals. 2004;20:259-266. DOI: 10.1016/S0960-0779(03)00373-4
  2. 2. Fan E, Hona YC. Generalized Tanh method extended to special types of nonlinear equations. Zeitschrift fur Naturforschung A. 2002;57:692-700. DOI: 10.1515/zna-2002-0809
  3. 3. Wazwaz AM. Soliton solutions for seventh-order Kawahara equation with time-dependent coefficients. Modern Physics Letters B. 2011;25:643-648. DOI: 10.1142/S0217984911026012
  4. 4. Optical and Quantum Electronics. 2020;52:511. DOI: 10.1007/s11082-020-02628-7
  5. 5. Alvaro H. Salas, computing exact solutions to a generalized lax seventh-order forced KdV equation (KdV7). Applied Mathematics and Computation. 2010;216(8):2333-2338

Written By

Alvaro Humberto Salas Salas

Submitted: 30 November 2023 Reviewed: 05 December 2023 Published: 03 May 2024